Question

How do you find the x and y intercepts for `y = 2x + 18`?

Answer 1

The plot crosses the y-axis when x=0 and it crosses the x-axis when y=0. So by substitution of 0 for one you find the value of the other by manipulation of the equation

Explanation:

If you meant to ask more than just how:

When `x=0`
`y=(2 times 0) + 18`

so the y-axis intercept is at `(x,y)->(0,18)`
For a strait line graph it is always at the value of the constant.

So at the x-axis intercept `y=0`

`0=2x+18`
`2x= -18`
`x= (-18)/2 = -9`

So the x-axis intercept is at `(x,y)-> (-9,0)`