# How do you find the x and y intercepts for y = -2x + 3?

Mar 29, 2018

see a step solution process below;

#### Explanation:

$y = - 2 x + 3$

Since the origin point of intersection is always zero, hence we would use its origin point to locate their intercepts.

To find the intercept of $x$, let $y = 0$

$y = - 2 x + 3$, where $y = 0$

$0 = - 2 x + 3$

$2 x = 3$

$x = \frac{3}{2} = 1.5$

Similarly, to find the intercept of $y$, let $x = 0$

$y = - 2 x + 3$, where $x = 0$

$y = - 2 \left(0\right) + 3$

$y = 0 + 3$

$y = 3$

Hence the $x \mathmr{and} y$ intercepts of the equation are $1.5 \mathmr{and} 3$ respectively..

Mar 29, 2018

$\text{x-intercept "=3/2," y-intercept } = 3$

#### Explanation:

$\text{to find the intercepts}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

$x = 0 \Rightarrow y = 0 + 3 = 3 \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \Rightarrow - 2 x + 3 = 0 \Rightarrow x = \frac{3}{2} \leftarrow \textcolor{red}{\text{x-intercept}}$
graph{-2x+3 [-10, 10, -5, 5]}