How do you find the x and y intercepts for #y=-2x+5#?

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Answer 1 · 2016-03-29T16:29:20

#x_(" intercept")=5/2 ->(x,y)->(5/2,0)#

#y_(" intercept")=5->(x,y)->(0,5)#

#y# intercept is when #x=0#

#x# intercept is when #y=0#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("To find "x_("Intercept"))#

Set #y=0# giving

#" "0=-2x+5#

Add #2x# to both sides

#" "2x=-2x+2x+5#

#" "2x=0+5#

Divide both sides by 2

#" "2/2xx x=5/2#

But #2/2=1#

#" "color(blue)(x=5/2)#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("To find "y_("Intercept"))#

Set #x=0#

#" "y=-2(0)+5#

#" "color(blue)(y=5)#