# How do you find the x and y intercepts for y= -5/3x+ 2?

Apr 11, 2018

(0,2) and (3,0)

#### Explanation:

The intercepts are when the $x \mathmr{and} y$ values are zero

$y = \frac{- 5}{3} x + 2$ when $x = 0$ is $y = 0 + 2$, $y = 2$

$y = \frac{- 5}{3} x + 2$ when $y = 0$ is $0 = \frac{- 2}{3} x + 2$

$\implies$ $- 2 = \frac{- 2}{3} x$ by subtracting 2 from each side

$\implies$ $- 6 = - 2 x$ by multiplying both sides by 3

$\implies$ $3 = x$ by dividing both sides by -2