How do you find the x and y intercepts for #y= -5/3x+ 2#?

1 Answer
Mark D.
Apr 11, 2018

(0,2) and (3,0)

Explanation:

The intercepts are when the #x and y# values are zero

#y=(-5)/3x+2# when #x=0# is #y=0+2#, #y=2#

#y=(-5)/3x+2# when #y=0# is #0=(-2)/3x+2#

#=># #-2=(-2)/3x# by subtracting 2 from each side

#=># #-6=-2x# by multiplying both sides by 3

#=># #3=x# by dividing both sides by -2

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