# How do you find the x and y intercepts for y=9/5x+3/5?

Jan 4, 2016

x = $- \frac{1}{3} \mathmr{and} y = \frac{3}{5}$

#### Explanation:

$y = \frac{9}{5}$x + $\frac{3}{5}$ is a linear equation ie. a straight line.

when a straight line crosses the x-axis the value of it's y-coordinate will be 0. By substituting y = 0 into the equation will enable us to find the corresponding x-coordinate.

y=0 : $\frac{9}{5}$ x + $\frac{3}{5}$ = 0

$\frac{9}{5}$x = $- \frac{3}{5}$

$x = - \frac{3}{5} / \frac{9}{5}$

$x = - \frac{3}{5} \times \frac{5}{9}$
$x = - \frac{1}{3}$
similarly when the straight line crosses the y-axis the value of it's x-coordinate will be 0 and by substituting x =0 into the equation will give the corresponding y- intercept.

x=0 : y = $\frac{9}{5} \times 0 + \frac{3}{5}$
$y = 0 + \frac{3}{5} = \frac{3}{5}$