How do you find the x and y intercepts for #y= x+2#?

1 Answer
Feb 14, 2016

Answer:

x-intercept: #(-2)#
y-intercept: #(+2)#

Explanation:

The x-intercept is the value of #x# when #y=0#
#color(white)("XXX")y=x+2# with #y=0#
#color(white)("XXX")rarr 0=x+2#
#color(white)("XXX") rarr x=-2#

The y-intercept is the value of #y# when #x=0#
#color(white)("XXX")y=x+2# with #x=0#
#color(white)("XXX")rarr y=0+2#
#color(white)("XXX")rarr y=2#

Occasionally you may get a teacher who wants the intercepts expressed as
(1) coordinates
#color(white)("XXX")#in which case the x-intercept is at #(-2,0)#
#color(white)("XXX")#and the y-intercept is at #(0,2)#
or
(2) an equation
#color(white)("XXX")#in which case the x-intercept is #x=-2#
#color(white)("XXX")#and the y-intercept is #y=2#