How do you find the x and y intercepts of 2x-6y=-12?

Apr 15, 2017

See the entire solution process below:

Explanation:

x- intercept)

Set $y$ equal to $0$ and solve for $x$:

$2 x - 6 y = - 12$ becomes:

$2 x - \left(6 \cdot 0\right) = - 12$

$2 x - 0 = - 12$

$2 x = - 12$

$\frac{2 x}{\textcolor{red}{2}} = - \frac{12}{\textcolor{red}{2}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{2}}} x}{\cancel{\textcolor{red}{2}}} = - 6$

$x = - 6$

The x-intercept is $- 6$ or $\left(- 6 , 0\right)$

y- intercept)

Set $x$ equal to $0$ and solve for $y$:

$2 x - 6 y = - 12$ becomes:

$\left(2 \cdot 0\right) - 6 y = - 12$

$0 - 6 y = - 12$

$- 6 y = - 12$

$\frac{- 6 y}{\textcolor{red}{- 6}} = \frac{- 12}{\textcolor{red}{- 6}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{- 6}}} y}{\cancel{\textcolor{red}{- 6}}} = 2$

$y = 2$

The y-intercept is $2$ or $\left(0 , 2\right)$