How do you find the x and y intercepts of #2x-6y=12#?

1 Answer
Mar 4, 2018

Answer:

X intercept=6
Y intercept=(-2)

Explanation:

If line ax+by+c=0,then
X-intercept#=(-c)/a,a!=0,#
Y-intercept#=(-c)/b,b!=0.#
We have,line #color(red)(2x-6y-12=0)rArra=2,b=-6,c=-12#
So,
X-intercept#=(-c)/a=(-(-12))/2=12/2=6#
Y-intercept#=(-c)/b=(-(-12))/(-6)=12/(-6)=-2#