# How do you find the x and y intercepts of 3x-4y=-12?

$\left(0 , 3\right) \mathmr{and} \left(- 4 , 0\right)$
$3 \cdot 0 - 4 y = - 12 \implies y = 3 \implies \left(0 , 3\right) \in r$
$3 x - 4 \cdot 0 = - 12 \implies x = - 4 \implies \left(- 4 , 0\right) \in r$