Question

How do you find the x and y intercepts of `3x-7y+20=0`?

Answer 1

x-intercept: `=a=-20/3`

y-intercept: `=b=20/7`

Explanation:

Given equation of straight line:

`3x-7y+20=0`

`3x-7y=-20`

`\frac{3x}{-20}+\frac{-7y}{-20}=1`

`\frac{x}{-20/3}+\frac{y}{20/7}=1`

Comparing the above equation with the intercept form of the straight line: `x/a+y/b=1` we get

x-intercept: `=a=-20/3`

y-intercept: `=b=20/7`

Answer 2

`"x-intercept "=-20/3," y-intercept "=20/7`

Explanation:

`"to find the intercepts, that is where the graph crosses"`
`"the x and y axes"`

`• " let x = 0, in the equation for y-intercept"`

`• " let y = 0, in the equation for x-intercept"`

`x=0rArr-7y=-20rArry=20/7larrcolor(red)"y-intercept"`

`y=0rArr3x=-20rArrx=-20/3larrcolor(red)"x-intercept"`