How do you find the x and y intercepts of #-4x=8y+12#?

2 Answers
Mar 29, 2017

Answer:

x-intercept: #(-3, 0)#
y-intercept: #(0, -3/2)#

Explanation:

The x-intercept occurs when the line crosses the x-axis. If you think about it, this point occurs when #y=0#.

#-4x=8*0+12=12# {substituted #y=0#}
#x=-3#

When #y=0#, #x=-3#. The x-intercept is therefore #(-3, 0)#.

The y-intercept occurs when the line crosses the y-axis. As above, this point occurs when #x=0#.

#-4*0=8y+12# {substituted #x=0#}
#y=-12/8=-3/2#

When #x=0#, #y=-3/2#. The y-intercept is therefore #(0, -3/2)#.

Mar 29, 2017

Answer:

#"y-intercept "=-3/2," x-intercept "=-3#

Explanation:

To find the #color(blue)"x and y intercepts"#

#• " let x = 0, in the equation, for y-intercept"#

#• " let y = 0, in the equation, for x-intercept"#

#x=0to8y+12=0to8y=-12toy=-3/2#

#y=0to-4x=0+12to-4x=12tox=-3#
graph{-1/2x-3/2 [-10, 10, -5, 5]}