# How do you find the x and y intercepts of -4x=8y+12?

Mar 29, 2017

x-intercept: $\left(- 3 , 0\right)$
y-intercept: $\left(0 , - \frac{3}{2}\right)$

#### Explanation:

The x-intercept occurs when the line crosses the x-axis. If you think about it, this point occurs when $y = 0$.

$- 4 x = 8 \cdot 0 + 12 = 12$ {substituted $y = 0$}
$x = - 3$

When $y = 0$, $x = - 3$. The x-intercept is therefore $\left(- 3 , 0\right)$.

The y-intercept occurs when the line crosses the y-axis. As above, this point occurs when $x = 0$.

$- 4 \cdot 0 = 8 y + 12$ {substituted $x = 0$}
$y = - \frac{12}{8} = - \frac{3}{2}$

When $x = 0$, $y = - \frac{3}{2}$. The y-intercept is therefore $\left(0 , - \frac{3}{2}\right)$.

Mar 29, 2017

$\text{y-intercept "=-3/2," x-intercept } = - 3$

#### Explanation:

To find the $\textcolor{b l u e}{\text{x and y intercepts}}$

• " let x = 0, in the equation, for y-intercept"

• " let y = 0, in the equation, for x-intercept"

$x = 0 \to 8 y + 12 = 0 \to 8 y = - 12 \to y = - \frac{3}{2}$

$y = 0 \to - 4 x = 0 + 12 \to - 4 x = 12 \to x = - 3$
graph{-1/2x-3/2 [-10, 10, -5, 5]}