# How do you find the x and y intercepts of -5x+10y=20?

Aug 13, 2017

See a solution process below:

#### Explanation:

One way to find the $x$ and $y$-intercepts is to set one variable equal to $0$ and solve for the other variable.

x-intercept:

Set $y = 0$ giving:

$- 5 x + \left(10 \cdot 0\right) = 20$

$- 5 x + 0 = 20$

$- 5 x = 20$

$\frac{- 5 x}{\textcolor{red}{- 5}} = \frac{20}{\textcolor{red}{- 5}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{- 5}}} x}{\cancel{\textcolor{red}{- 5}}} = - 4$

$x = - 4$

The $x$-intercept is: $- 4$ or $\left(- 4 , 0\right)$

y-intercept:

Set $x = 0$ giving:

$\left(- 5 \cdot 0\right) + 10 y = 20$

$0 + 10 y = 20$

$10 y = 20$

$\frac{10 y}{\textcolor{red}{10}} = \frac{20}{\textcolor{red}{10}}$

$\frac{\textcolor{red}{\cancel{\textcolor{b l a c k}{10}}} y}{\cancel{\textcolor{red}{10}}} = 2$

$y = 2$

The $y$-intercept is: $2$ or $\left(0 , 2\right)$