How do you find the x and y intercepts of #6x+2y=10#?

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Answer 1 · 2016-11-07T13:31:55

The intercepts are at #(1 2/3, 0) and (0, 5)#

Leave the equation #6x +2y = 10# in this form.

All along the #x-#axis, #y=0" "# All along the #y-#axis, #x=0#

To find the #y-#intercept, set #x=0#

#6(0) + 2y = 10" "rarr y = 5#

To find the #x-#intercept, set #y=0#

#6x + 2(0) = 10" " rarr x = 10/6 = 5/3 = 1 2/3#

The intercepts are at #(1 2/3, 0) and (0, 5)#