# How do you find the x and y intercepts of 6x+2y=10?

Nov 7, 2016

The intercepts are at $\left(1 \frac{2}{3} , 0\right) \mathmr{and} \left(0 , 5\right)$

#### Explanation:

Leave the equation $6 x + 2 y = 10$ in this form.

All along the $x -$axis, $y = 0 \text{ }$ All along the $y -$axis, $x = 0$

To find the $y -$intercept, set $x = 0$

$6 \left(0\right) + 2 y = 10 \text{ } \rightarrow y = 5$

To find the $x -$intercept, set $y = 0$

$6 x + 2 \left(0\right) = 10 \text{ } \rightarrow x = \frac{10}{6} = \frac{5}{3} = 1 \frac{2}{3}$

The intercepts are at $\left(1 \frac{2}{3} , 0\right) \mathmr{and} \left(0 , 5\right)$