How do you find the x and y intercepts of #y=3x-2#?

2 Answers
Apr 19, 2018

Answer:

#"x-intercept "=2/3," y-intercept "=-2#

Explanation:

#"To find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArry=0-2=-2larrcolor(red)"y-intercept"#

#y=0rArr3x-2=0rArrx=2/3larrcolor(red)"x-intercept"#
graph{(y-3x+2)((x-0)^2+(y+2)^2-0.04)((x-2/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Apr 19, 2018

Answer:

#"y-intercept " = (0, -2) or -2#
#"y-intercept " = (2/3, 0) or 2/3#

Explanation:

The y-intercept is when the value of #x = 0#. Therefore, plugging in the value of #x# into the equation:

#3(0) - 2 = -2 " So, " y = -2# This is for the y-intercept

The x intercept is when #y = 0#, substituting this into the equation gives us:

#0 = 3x - 2# It is possible to rearrange this:

# 0 -3x = 3x - 3x - 2#
# 3x = 2#
# x = 2/3#