# How do you find the x and y intercepts of y=3x-2?

Apr 19, 2018

$\text{x-intercept "=2/3," y-intercept } = - 2$

#### Explanation:

$\text{To find the intercepts, that is where the graph crosses}$
$\text{the x and y axes}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

$x = 0 \Rightarrow y = 0 - 2 = - 2 \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \Rightarrow 3 x - 2 = 0 \Rightarrow x = \frac{2}{3} \leftarrow \textcolor{red}{\text{x-intercept}}$
graph{(y-3x+2)((x-0)^2+(y+2)^2-0.04)((x-2/3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

Apr 19, 2018

$\text{y-intercept } = \left(0 , - 2\right) \mathmr{and} - 2$
$\text{y-intercept } = \left(\frac{2}{3} , 0\right) \mathmr{and} \frac{2}{3}$

#### Explanation:

The y-intercept is when the value of $x = 0$. Therefore, plugging in the value of $x$ into the equation:

$3 \left(0\right) - 2 = - 2 \text{ So, } y = - 2$ This is for the y-intercept

The x intercept is when $y = 0$, substituting this into the equation gives us:

$0 = 3 x - 2$ It is possible to rearrange this:

$0 - 3 x = 3 x - 3 x - 2$
$3 x = 2$
$x = \frac{2}{3}$