How do you find the x intercept of #4x-12=0 #?

1 Answer
Aug 21, 2017

Answer:

Replace #y# with #0# (if there is a #y#), then solve for #x#. The #x#-intercept is at #x=3#.

Explanation:

The equation #4x-12=0# is for a vertical line, since (the non-existent) #y# does not depend on #x#. We can solve this for #x# as follows:

#4x-12=0#
#4xcolor(white)- color(white)12=12#
#color(white)4 xcolor(white)- color(white)12=3#

Meaning, for any #y# we choose, we will always get #x=3#. And since the #x#-intercept occurs where #y=0#, we know that value of #y# will also give us #x=3#. Thus, our intercept is at #x=3#.

Here is a graph of the line #4x-12=0#:

graph{4x-12=0.0000001y [-10, 10, -5, 5]}