# How do you find the zero of f(x)=4x-12?

Oct 28, 2017

Solve the equation for $x$, when $f \left(x\right) = 0$
Then, $x = 3$.

#### Explanation:

I assume you mean to find the solution/root (radical) $x$, when $f \left(x\right) = 0$.

Then, this is simple.
Just set $f \left(x\right)$ to 0 and solve the equation for $x$:

$f \left(x\right) = 4 x - 12 = 0$

First we can add 12 on both sides of the equality:

$4 x - 12 + 12 = 0 + 12$
which becomes
$4 x = 12$

We can now divide both sides of the equality by 4:
$\frac{4 x}{4} = \frac{12}{4}$
and we have
$x = 3$

The "zero", or the solution for $f \left(x\right) = 0$ is $x = 3$.
Q.E.D.