How do you find the zeroes for #f(x) = x^3 + 2x^2 - 5x - 6#?
1 Answer
Sep 13, 2015
-1,2,-3
Explanation:
The real zeros would be out of the factors of 6, may be
Consider -1 first, it makes f(-1)=0 hence -1 is one of the zeros. Like wise x=2 and x= -3 also makes f(2)=0 and f(-3)=0.
Thus all the three zeros are determined. These are -1,2 and -3
