# How do you find the zeroes of f(x)=x^2+25?

Apr 24, 2018

$x = 5 i$

#### Explanation:

Given: $f \left(x\right) = {x}^{2} + 25$.

The zeroes of $f \left(x\right)$ are values for $x$ such that $f \left(x\right) = 0$.

So we have:

${x}^{2} + 25 = 0$

${x}^{2} = - 25$

$x = \sqrt{- 25}$

$x = 5 i$