How do you find the zeroes of #f(x) = x^4 -24x^2- 25#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer George C. May 30, 2015 #x^4-24x^2-25# #=(x^2-25)(x^2+1)# #=(x-5)(x+5)(x^2+1)# #x^2+1 > 0# for all #x in RR# So the only zeros are given by #x = -5# and #x = 5#. Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 2783 views around the world You can reuse this answer Creative Commons License