# How do you find the zeros for the function f(x)=(x^2-x-6)/(x^2+8x+12)?

The zero is $3$.
In this problem, when you factor the top, you get $\left(x - 3\right) \left(x + 2\right)$ so your possible zeros are $3$ and -$2$, but when you factor the bottom you get $\left(x + 2\right) \left(x + 6\right)$ meaning that if you were to plug -$2$ into your original equation, your answer would be undefined, so your only zero would be $3$.