Question

How do you find the zeros, if any, of `y= -x^2 -3x +17`using the quadratic formula?

Answer 1

`x=-3/2+-sqrt77/2` are the two zeros

Explanation:

You would solve the equation `-x^2-3x+17=0`

Let's apply the quadratic formula:

`x=(-b+-sqrt(b^2-4ac))/(2a)`

`x=(3+-sqrt(9-4(-1)*17))/-2`

`=(3+-sqrt(77))/-2`

`=-3/2+-sqrt77/2`