# How do you find the zeros, if any, of y= -x^2 -3x +17 using the quadratic formula?

Mar 15, 2017

$x = - \frac{3}{2} \pm \frac{\sqrt{77}}{2}$ are the two zeros

#### Explanation:

You would solve the equation $- {x}^{2} - 3 x + 17 = 0$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$
$x = \frac{3 \pm \sqrt{9 - 4 \left(- 1\right) \cdot 17}}{-} 2$
$= \frac{3 \pm \sqrt{77}}{-} 2$
$= - \frac{3}{2} \pm \frac{\sqrt{77}}{2}$