How do you find the zeros, if any, of y= -x^2 -5x+2using the quadratic formula?

Apr 7, 2017

Zeros are $x \approx - 5.37 , x \approx 0.37$

Explanation:

Quadratic equation is $y = a {x}^{2} + b x + c$

y= -x^2 -5x +2 ; a = -1 , b= -5 , c=2 ; D= b^2-4*a*c = 25 +8 =33 (+)
Since D is positve, roots are real.

Roots are $x = - \frac{b}{2 a} \pm \frac{\sqrt{{b}^{2} - 4 a c}}{2 a} \mathmr{and} x = \frac{5}{-} 2 \pm \frac{\sqrt{33}}{-} 2 \mathmr{and} x = - 2.5 \pm \left(- 2.87\right) \therefore x = - 2.5 - 2.87 \approx - 5.37 \mathmr{and} x \approx 0.37$ [Ans]