Question

How do you find the zeros of a function `(x^3 - 5x^2+ 4x )/(-4x^2 + 36)`?

Answer 1

First, factor the function:

`f(x) = [x(x^2 - 5x + 4)]/[4(9 - x^2)] = [x(x - 1)(x - 4)]/[4(3 - x)(3 + x)]`

Answers: x = 0; x = 1; and x = 4.