# How do you find the zeros of a function (x^3 - 5x^2+ 4x )/(-4x^2 + 36)?

$f \left(x\right) = \frac{x \left({x}^{2} - 5 x + 4\right)}{4 \left(9 - {x}^{2}\right)} = \frac{x \left(x - 1\right) \left(x - 4\right)}{4 \left(3 - x\right) \left(3 + x\right)}$