# How do you find the zeros of f(x)=x^2-5x-6 by factoring?

Zeros of the function $f \left(x\right)$ are $x = 6 \ast \mathmr{and} \ast x = - 1$
$f \left(x\right) = {x}^{2} - 5 x - 6 = \left(x - 6\right) \left(x + 1\right) = 0 \therefore \left(x - 6\right) = 0 \mathmr{and} \left(x + 1\right) = 0$
So Zeros of the function are $x = 6 \mathmr{and} x = - 1$[Ans]