How do you find the zeros of #g(x)=x^4-5x^2-36#? Precalculus Complex Zeros Complex Conjugate Zeros 1 Answer Douglas K. Nov 1, 2016 #g(x) = x^4 - 5x^2 - 36# has 4 zeros, #x = -3, 3, -2i and 2i# Explanation: Given: #g(x) = x^4 - 5x^2 - 36# Let #u = x^2# #g(u) = u^2 - 5u - 36 = 0# #0 = u^2 - 5u - 36# #0 = (u -9)(u + 4)# #u = 9 and u = -4# #x = +-3 and x = +-2i# #g(x) = x^4 - 5x^2 - 36# has 4 zeros, #x = -3, 3, -2i and 2i# Answer link Related questions What is a complex conjugate? How do I find a complex conjugate? What is the conjugate zeros theorem? How do I use the conjugate zeros theorem? What is the conjugate pair theorem? How do I find the complex conjugate of #10+6i#? How do I find the complex conjugate of #14+12i#? What is the complex conjugate for the number #7-3i#? What is the complex conjugate of #3i+4#? What is the complex conjugate of #a-bi#? See all questions in Complex Conjugate Zeros Impact of this question 1670 views around the world You can reuse this answer Creative Commons License