# How do you find the zeros of the function #f(x)=(3x^2-18x+24)/(x-6)#?

##### 1 Answer

Jun 5, 2017

#### Explanation:

#"zeros are the values of x that make f(x) equal zero"#

#rArr(3x^2-18x+24)/(x-6)=0#

#"the numerator therefore must equal zero"#

#"solve " 3x^2-18x+24=0" for zeros"#

#3(x^2-6x+8)=0larr" common factor of 3"#

#3(x-2)(x-4)=0#

#"equate each factor to zero"#

#x-2=0tox=2#

#x-4=0tox=4#