How do you find the zeros of the function #f(x)=(3x^2-18x+24)/(x-6)#?
1 Answer
Jun 5, 2017
Explanation:
#"zeros are the values of x that make f(x) equal zero"#
#rArr(3x^2-18x+24)/(x-6)=0#
#"the numerator therefore must equal zero"#
#"solve " 3x^2-18x+24=0" for zeros"#
#3(x^2-6x+8)=0larr" common factor of 3"#
#3(x-2)(x-4)=0#
#"equate each factor to zero"#
#x-2=0tox=2#
#x-4=0tox=4#
