# How do you find the zeros of the function f(x)= x^2-2x-4?

The zeros of this function are ${x}_{1} = 1 - \sqrt{5}$ and ${x}_{2} = 1 + \sqrt{5}$
To find the zeros of a quadratic function you first have to calculate $\Delta$. In this case it is $\Delta = {\left(- 2\right)}^{2} - 4 \cdot 1 \cdot \left(- 4\right) = 20$
$\Delta > 0$ so function has 2 real zeros which can be calculated using:
${x}_{1} = \frac{- b - \sqrt{\Delta}}{2 a}$ and ${x}_{2} = \frac{- b + \sqrt{\Delta}}{2 a}$