# How do you find the zeros of the function #f(x)=(x^2-x-12)/(x^2+2x-35)#?

##### 1 Answer

Mar 22, 2018

#### Explanation:

#"to find the zeros equate the numerator to zero and solve"#

#"solve "x^2-x-12=0#

#"The factors of - 12 which sum to - 1 are - 4 and + 3"#

#rArr(x-4)(x+3)=0#

#"equate each factor to zero and solve for x"#

#x-4=0rArrx=4#

#x+3=0rArrx=-3#

graph{(x^2-x-12)/(x^2+2x-35 [-10, 10, -5, 5]}