Question

How do you find the zeros of the function `f(x)=(x^3-4x^2-12x)/(x+2)`?

Answer 1

0 and 6. The invisible and indeterminate hole ( break ) is marked in the Socratic graph, at (-2, 16).

Explanation:

`f=x(x-6)((x+2)/(x+2))`, with a hole at `x = -2`.

Sans the hole, `f= x(x-6)`. and the zeros are x = 0 and 6.

graph{(x(x-6)-y)((x+2)^2+(y-16)^2-.2)=0 [-32, 32, -11, 20]}