How do you find the zeros of the function #f(x)=(x^3+x^2-6x)/(x-1)#?
1 Answer
May 4, 2017
Explanation:
#"the zeros are the values of x that make f(x)=0"#
#"The denominator of "f(x)!=0#
#"as this would make f(x) undefined"#
#"equate the numerator to zero and solve"#
#rArrx^3+x^2-6x=0rarr" factor out x"#
#rArrx(x^2+x-6)=0#
#rArrx(x+3)(x-2)=0#
#rArrx=0,x=-3,x=2larr" are the zeros"#
