# How do you find the zeros of the polynomial function with equation f(x) = 3(x+5)(x+2)^2?

Dec 1, 2016

$x = - 5 \text{ and "x=-2" }$ for $f \left(x\right) = 0$

#### Explanation:

Set as:$\text{ } 3 \left(x + 5\right) {\left(x + 2\right)}^{2} = 0$

Divide both sides by 3

$\left(x + 5\right) {\left(x + 2\right)}^{2} = 0$

So

$\left(x + 5\right) = 0 \implies x = - 5$

Or

${\left(x + 2\right)}^{2} = 0 \implies x = - 2$