How do you find the zeros of the polynomial function with equation #f(x) = 3(x+5)(x+2)^2#?

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Answer 1 · 2016-12-01T17:30:28

#x=-5" and "x=-2" " # for #f(x)=0#

Set as:#" "3(x+5)(x+2)^2=0#

Divide both sides by 3

#(x+5)(x+2)^2=0#

So

#(x+5) = 0 => x=-5#

Or

#(x+2)^2=0=>x=-2#

Tony B