# How do you find the zeros of # (-x+1)(x+2)(x-3)^2#?

##### 1 Answer

Mar 26, 2016

There are four zero in total: at

graph{(-x+1)(x+2)(x-3)^2 [-7.116, 10.05, -12.5, 34.3]}

#### Explanation:

Given:

Required the zeros?

Solution Strategy: Since

There are four zero in total: at