How do you find the zeros of #x^2-4x-12#?

1 Answer
Apr 1, 2018

Answer:

Factor the expression, if possible.
#x = -2# and #x = 6#

Explanation:

The "zeros" of the expression are found in one method by creating a simpler set of factors and then finding the zeros of those parts.
There are other tutorials online that explain the factoring process in more detail. For this example:
#x^2 − 4x − 12 = (x +2)xx(x - 6)#

Setting each of these factors to zero we obtain:
#(x +2) = 0#; #x = -2# AND
#(x - 6) = 0#; #x = 6# are zeros of the function.