How do you find the zeros of #x^3-x^2-10x-8#?

1 Answer
May 25, 2016

Answer:

#x=# Either -1 or -2 or +4

Explanation:

#f(x) = x^3-x^2-10x-8#

To find the zeros of this polynomial function we must find all values of x such that #f(x) = 0#

Notice that #f(x)# factorises to #(x+1)(x^2-2x-8)#
Which further factorises to #(x+1)(x+2)(x-4)#

Hence the zeors of #f(x)# occur when #(x+1)(x+2)(x-4) =0#

This occurs when either #(x+1)=0# or #(x+2)=0# or #(x-4)=0#

Therefore the zeros of #f(x)# are either -1 or -2 or +4