# How do you find the zeros of  y = 4/5x^2 - 7/2x + 2/3  using the quadratic formula?

May 26, 2018

${x}_{1} = \frac{35}{16} + \frac{\sqrt{9195}}{48}$ or ${x}_{2} = \frac{35}{16} - \frac{\sqrt{9105}}{48}$

#### Explanation:

Multiplying the whole equation by $30$
$24 {x}^{2} - 105 x + 20 = 0$
then we get
${x}^{2} - \frac{105}{24} x + \frac{5}{6} = 0$
${x}_{1 , 2} = \frac{35}{16} \pm \sqrt{{\left(\frac{35}{16}\right)}^{2} - \frac{5}{6}}$
${x}_{1 , 2} = \frac{35}{16} \pm \setminus \sqrt{\frac{3035}{768}}$
${x}_{1 , 2} = \frac{35}{16} \pm \setminus \frac{\sqrt{9105}}{48}$