# How do you find the zeros of  y=x(x-1)(x+2)^2?

Mar 5, 2016

0,1,$- 2 \mathmr{and} - 2$

#### Explanation:

Equate each factor of yr to 0.
$- 2$ is a double root.
The points at which this curve meets the x-axis are ( 0, 0 , ( 1, 0 ) and ( -2, 0 )
At the double point ($- 2$, 0 ), $\frac{\mathrm{dy}}{\mathrm{dx}}$ = 0.