How do you find the zeros, real and imaginary, of #y=19x^2-4x-3 #using the quadratic formula?
The problem says to use the quadratic formula, so we will use that. The quadratic formula is
The equation is already in standard form, so we can simply substitute and simplify!
244 is not a perfect square, so we could stop here. However, notice that 244 is divisible by 4, which is a perfect square, so we can simplify
We can pull a 2 out of each term and simplify:
So our solutions are