# How do you find the zeros, real and imaginary, of y= 3x^2-43x-33 using the quadratic formula?

Jun 9, 2018

color(indigo)(x = (43 + sqrt2245)/6, (43-sqrt2245)/6

#### Explanation:

$y = 3 {x}^{2} - 43 x - 33$

$a = 3 , b = - 43 , c = - 33$

$\text{Quadratic formula is } x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$x = \frac{43 \pm \sqrt{{43}^{2} + \left(4 \cdot 3 \cdot 33\right)}}{6}$

color(indigo)(x = (43 + sqrt2245)/6, (43-sqrt2245)/6