How do you find the zeros, real and imaginary, of #y= 3x^2-43x-73# using the quadratic formula?

1 Answer
Jun 14, 2016

Answer:

The zeros of the given Quadratic Polynomial are #(43+-sqrt(2725))/6.#

Explanation:

Formula to find the zeros, say #alpha# & #beta,# of a Quadratic Polynomial #y=P(x)=ax^2+bx+c# is

#alpha,beta=(-b+-sqrt(b^2-4ac))/(2a)#

In our case, #a=3, b=-43,c=-73.#
#:. alpha,beta= {43+-sqrt(1849+876)}/6=(43+-sqrt(2725))/6.#

We note that since #Delta=b^2-4ac=2725>0#, the given quadratic can not have any complex zero.