Question

How do you find the zeros, real and imaginary, of `y=- 5x^2-22x+10` using the quadratic formula?

Answer 1

`(11 +- 3sqrt19)/5`

Explanation:

Use the improved quadratic formula (Socratic Search)
`y = -5x^2 - 22x + 10 = 0`
`D = d^2 = b^2 - 4ac = 484 + 200 = 684 = 36(19)`
`d = +- 6sqrt19`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = 22/10 +- (6sqrt19)/-10 = (11 +- 3sqrt19)/5`