Question

How do you find the zeros, real and imaginary, of `y= 7x^2+4x-24` using the quadratic formula?

Answer 1

`x = - 4/14 +- 26.23/14`

Explanation:

y = 7x^2 + 4x - 24.
`D = d^2 = b^2 - 4ac = 16 + 672 = 688` --> `d = +- 26.23`
There are 2 real roots:
`x = -b/(2a) +- d/(2a) = - 4/14 +- 26.23/14`