How do you find the zeros, real and imaginary, of #y= 7x^2-6x+14# using the quadratic formula?
By plugging in the coefficients and constant as a, b, and c into the quadratic formula.
The quadratic formula is
The a, b, and c refers to a, b, and c in standard form which is
Now we begin the process of plugging into the formula.
Now at this point, I can stop because I know all the answers are imaginary, we know this because under the square root, there will be a negative number when we take 392 from 36. Because of this, the answers are imaginary.