# How do you find the zeros, real and imaginary, of y=9x^2-32+2 using the quadratic formula?

May 24, 2018

$y = 9 {x}^{2} - 32 + 2 = 9 {x}^{2} - 30$

To find zeros $9 {x}^{2} - 30 = 0$

$9 {x}^{2} = 30$

${x}^{2} = \frac{30}{9} = \frac{10}{3}$

$x = \pm \sqrt{\frac{10}{3}} = \pm \frac{\sqrt{10}}{\sqrt{3}} = \pm \frac{\sqrt{30}}{3}$

There is no imaginary solutions, both roots are real numbers