# How do you find the zeros, real and imaginary, of y=x^2-2x-4 using the quadratic formula?

Jul 1, 2016

$x = 1 \pm \sqrt{5}$

#### Explanation:

Using the quadratic formula, you have:

$x = 1 \pm \sqrt{1 + 4}$

$x = 1 \pm \sqrt{5}$

that are real solutions