How do you find the zeros, real and imaginary, of #y=x^2+3x+7# using the quadratic formula?
Plug the equation into the formula and solve for x. These will be your zeroes.
plug in the values from the equation
then solve for x...
This gives 2 imaginary zeroes, but does not give any real zeroes, and if you graph the equation you will see that the equation does not have any.