Question

How do you find the zeros, real and imaginary, of `y=-x^2- 5x -35` using the quadratic formula?

Answer 1

`-5/2 + i sqrt(115)/2 and -5/2 -i sqrt(115)/2`

Explanation:

For zeros, y=0, which makes it `x^2+5x+35=0`. Solution using quadratic formula, is appended below#