Question

How do you find the zeros, real and imaginary, of `y= -x^2-5x+37` using the quadratic formula?

Answer 1

`x = - 5/2 +- sqrt173/2`

Explanation:

`D = d^2 = b^2 - 4ac = 25 + 148 = 173` --> `d = +- sqrt173`
`x = -b/(2a) +- d/(2a) = - 5/2 +- sqrt173/2`