# How do you find the zeros, real and imaginary, of y= -x^2-5x+37  using the quadratic formula?

$x = - \frac{5}{2} \pm \frac{\sqrt{173}}{2}$
$D = {d}^{2} = {b}^{2} - 4 a c = 25 + 148 = 173$ --> $d = \pm \sqrt{173}$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = - \frac{5}{2} \pm \frac{\sqrt{173}}{2}$