Question

How do you find three consecutive odd integers if three times the middle integer increased by the largest is 38?

Answer 1

The three consecutive odd integers are `7`, `9` and `11`.

Explanation:

Let the three consecutive odd integers be `x`, `x+2` and `x+4`.

As three times the middle number `x+2` is increased bt the largest i.e. `x+4`, it becomes `3(x+2)+x+4=3x+6+x+4=4x+10`.

Hence `4x+10=38`

i.e. `4x=38-10=28` or `x=28/4=7`

Hence the three consecutive odd integers are `7`, `9` and `11`.