Question

How do you find two solutions (in degree and radians) for `sec x= (-2sqrt3)/3`?

Answer 1

Solve `sec x = (-2sqrt3)/3`

Ans: `+- (5pi)/6`

Explanation:

`sec x = - (2sqrt3)/3 = - 2/sqrt3` --> `cos x = - sqrt3/2`
Trig Table of Special Arc -->
`cos x = - sqrt3/2` --> `x = +- (5pi)/6` or `x = +- 150` deg