Question

How do you find two solutions of the equations `cottheta=-sqrt3`?

Answer 1

`(5pi)/6, (11pi)/6`

Explanation:

`cot t = 1/(tan t) = - sqrt3` --> `tan t = - 1/sqrt3 = - sqrt3/3`.
Use trig table of special arcs and unit circle:
`tan t = - sqrt3/3` --> 2 solutions -->
`t = (5pi)/6`, and `t = (5pi)/6 + pi = (11pi)/6`
Answers for `(0, 2pi)`
`(5pi)/6, (11pi)/6`